A garrison of 200 men had provisions for 45 days. After 15 days ,40 more men join the garrison. Find the number of days for which the remaining food will last.
Answers
Answered by
155
Hi ,
This is related to Inverse Proportion.
If two quantities are so related that
an increase in one causes a
corresponding decrease in the other
( or vice versa ) then they are said
to be in Inverse variation.
If two quantities x and y are in
Inverse variation then
x × y = k ( constant )
200 men had provisions for 45 days.
After 15 days ,
200 men had provisions for 30days.
Now ,
i ) Number of men ( x1 ) = 200
Provisions finished ( y1 ) = 30 days
ii ) after 15 days number of men
joined are 40.
Therefore,
Number of men
after 15 days ( x2 ) = 240
Let food last in Number of days = y2
x2 × y2 = x1 × y1
y2 = ( x1 × y1 ) / x2
y2 = ( 200 × 30 ) / 240
= 25
Therefore,
Remaining food will last in 25days.
I hope this helps you.
:)
This is related to Inverse Proportion.
If two quantities are so related that
an increase in one causes a
corresponding decrease in the other
( or vice versa ) then they are said
to be in Inverse variation.
If two quantities x and y are in
Inverse variation then
x × y = k ( constant )
200 men had provisions for 45 days.
After 15 days ,
200 men had provisions for 30days.
Now ,
i ) Number of men ( x1 ) = 200
Provisions finished ( y1 ) = 30 days
ii ) after 15 days number of men
joined are 40.
Therefore,
Number of men
after 15 days ( x2 ) = 240
Let food last in Number of days = y2
x2 × y2 = x1 × y1
y2 = ( x1 × y1 ) / x2
y2 = ( 200 × 30 ) / 240
= 25
Therefore,
Remaining food will last in 25days.
I hope this helps you.
:)
Answered by
14
Answer: 25 days
Step-by-step explanation:
Similar questions