Three numbers are selected at random without replacement from first six positive integers. If X denotes the smallest of the three numbers obtained find the probability distribution of X also find the mean and variance of the distribution.
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Thanks for asking the question.
We have to select numbers from first 6 positive integers, i.e., the numbers are 1,2,3,4,5,6.
If three numbers are selected then probability of x being smallest number out of the other three will be 4/6= 2/3
Hope it helps.
We have to select numbers from first 6 positive integers, i.e., the numbers are 1,2,3,4,5,6.
If three numbers are selected then probability of x being smallest number out of the other three will be 4/6= 2/3
Hope it helps.
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