Three particles of masses 1kg, 2kg and 3kg are placed at the corners A, B and C respectively of an equilateral triangle ABC of edge 1m. Find the distance of their centre of mass from A.
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took A to be on the y axis to maki it easier....u can choose urselved
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m
1
=1 kg,
x
1
=0,
y
1
=0,
m
2
=2 kg,
x
2
=1,
y
2
=0,
m
3
=3 kg
x
3
=1/2
y
3
=
3
/2
The position of centre of mass is
C. M=(
m
1
+m
2
+m
3
m
1
x
1
+m
2
x
2
+m
3
x
3
,
m
1
+m
2
+m
3
m
1
y
1
+m
2
y
2
+m
3
y
3
)
=(
1+2+3
(1×0)+(2×1)+(3×1/2)
,
1+2+3
(1×0)+(2×0)+(3×(
3
/2))
)
=(
12
7
,
12
3
3
) from the point B
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