Question

Three pieces of timber 42 m, 49 m and 63 m long have to be divided into planks of the same length. What is the greatest possible length of each plank??​

Answer 1

Answer:

Write 42 ,49 and 63 as product of prime factors and find their HCF

$42=2×3×7$

$49=7×7$

$63=3×3×7$

Therefore,

$<strong>HCF</strong>(42,49,63)=7$

Greatest possible plank of equal length $= 7m$