Three resistor 5 Omh ,4 Omh and 20omh are connected in parallel calculate combined resistance
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0.5 ohms
all three resistance are connected in parallel so we have a formula of 1 by equalent is equal to R1+R2+R3 so according to my question we add this three resistance (1 by 5 + 1 by 4 + 1 by 20)ohms that is 0.5ohms
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