three resistor of 10 ohm 15 ohm and 20 ohm are connected in series in the circuit.If p.d drop across 15ohm resistor is 3v ,find the current in the circuit and potential drop across the 10ohm resistor
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R(1) = 10 ohm
R(2)= 15 ohm
R(3) = 20 ohm
V(2) = 3v
I = V/R
=3/15 = 0.2A
Since current in series circuit across each resistor remains same,
I = 0.2
Now,
R(1) = 10ohm
I = 0.2 A
V = I R
= 0.2(10) = 2 v.
Hence, current across circuit is 0.2 A and potential drop across 10 ohm resistor is 2v
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