three solid mental cubes with edges 6 cm , 8cm,10cm respectively are melted together and formed into a single cube find the volume of new cubes
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1
Volume remains same so
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cuberoot of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm
volume of new cube = v1+v2+v3
= 6^3+8^3+10^3
=216+512+1000
=1728
now volume of new cube = a^3= 1728
edge of new cube = a= cuberoot of 1728
a= 12
therefore surface area of new cube = 6 a^2
=6×12^2
=6×12×12
=864 square cm
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8
Volume of cube with side 6cm = 6 x 6 x 6 = 216cm³
Volume of cube with side 8 cm = 8 x 8 x 8 = 512 cm³
Volume of cube with side 10 cm = 10 x 10 x 10 = 1000 cm³
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Volume of 3 cubes = 216 x 512 x 1000 = 1728 cm³
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Answer : Volume of the single big cube = 1728 cm³
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