three solid spheres of radius 3 cm, 4 cm and 5 cm are melted and recasted into a solid sphere. what will be the percentage decrease in the surface area?
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Answered by
6
The total volume of the three spheres is:
(4/3)π(3)3 + (4/3)π(4)3 + (4/3)π(5)3
= (4/3)π(33+43+53)
= (4/3)π(216)
= (4/3)π(6)3
The "new" sphere would have radius = 6 cm
(4/3)π(3)3 + (4/3)π(4)3 + (4/3)π(5)3
= (4/3)π(33+43+53)
= (4/3)π(216)
= (4/3)π(6)3
The "new" sphere would have radius = 6 cm
Answered by
2
❤❤Here is your answer ✌ ✌
Total volume of three sphere is:-
4/3π(3)3 +4/3π(4)3+ 4/3π(5)3
4/3π{27+64+125}
4/3π{216}
4/3π×216
4π×72
288π
Total volume of three sphere is:-
4/3π(3)3 +4/3π(4)3+ 4/3π(5)3
4/3π{27+64+125}
4/3π{216}
4/3π×216
4π×72
288π
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