Three times the smallest of three consecutive odd number decreased by 7 equal twice the largest one find the number
Answers
Answered by
2
Answer:
: 15, 17 and 19
Step-by-step explanation:
Numbers are n, n+2 and n+4
3n-7 = 2(n+4)
3n-7 = 2n+8
3n-2n = 8+7
n = 15
Answer: 15, 17 and 19
Answered by
1
Step-by-step explanation:
Let smallest no. be x
Nos. = x, x+2, x+4
ATQ, 3x - 7 = 2(x+4)
=> 3x-7 = 2x + 8
=> 3x - 2x = 8+7
=> x=15
Therefore number = 15
Hope it helps
Similar questions