Question

three times the smallest of three consecutive odd numbers decreased by 7 equals twice the largest one. Find the numbers.

Answer 1

Let the numbers be x, x+2 & x+4

ATQ,

(3x-7) = 2(x+4)

3x-7 = 2x+8

3x-2x = 8+7

x=15

Thus,

No. are :

x=15

x+2=15+2=17

x+4=15+4=19

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