time after which total acceleration of particle makes
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Explanation:
Acceleration along the tangent(aT)=d/dt(2t^2)=4t.
At t=1 s, aT=4*1=4 m/s^2.
Speed at t=1 s (v1)=2*1*1= 2 m/s.
Acceleration towards the centre (aC)=v^2/r=2*2/1=4 m/s^2.
Total acceleration=√((aT*aT)+(aC*aC))=4√2 m/s^2.
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