Physics, asked by priyakashyap5205, 1 year ago

Time period of a particle executing shm is 8 second it is equal to zero it is at mean position the ratio of the distance covered by the particle in the first second and 2 ii ii

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Answered by Anonymous
1

Answer:

Total Energy of Particle Performing Linear S.H.M.:

Since for a given S.H.M., the mass of body m, angular speed ω and amplitude a are constant, Hence the total energy of a particle performing S.H.M. ... The total energy of a linear harmonic oscillator is directly proportional to the square of its amplitude

Answered by sakshisahu765
0

Answer:

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