Question

to check the correctness of equation V=u+2as

Answer 1

We can check the correctness of equation by Dimensional Analysis.Equation:
V²-U²=2aswhere
V=u=velocities = Dimension=LT⁻¹a= acceleration=ΔV/T=LT⁻¹/T=LT⁻²S=Distance=LR.H.S=2as=2x[LT⁻²]x[L]=[L²T⁻²]L.H.S=v²-u²=[LT⁻¹]²=[L²T⁻²]
Therefore L.H.S=R.H.S