Question

To construct a right triangle whose base is 12 cm and sum
of its hypotenuse and other side is 18 cm. We draw line
segment AB of 12 cm. Draw a ray AX making 90° with AB.
The next step is:
(a) Cut a line segment AD of 18 cm on AX
(b) Cut a line segment BD of 18 cm
(c) Cut a line segment AD of 18 cm on AB
(d) Cut a line segment BD of 18 cm on AB
By following these steps of construction, (i) Draw a line
segment PQ = 11 cm (ii) At P construct an angle of 60°
and at Q, an angle of 45.. (iii) Bisect these angles. Let the
bisectors of these angles intersect at a point A. (iv) Draw
perpendicular bisectors DE of AP to intersect PQ at B and
FG of AQ to intersect PQ at C. (v). Join AB and AC. Triangle
ABC has been obtained. In this AABC,
(a) AB + BC + CA = 11 cm (b) AB + BC = 11 cm
(c) BC + CA = 11 cm (d) AB + BC + CA > 11 cm
utan ofn mixen angle, as shown​

Answer 1

Answer:

sorry I don't know this answer