Question

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a piston is compressed from a volume of 8.3L and 2.8L against a constant pressure of 2 bar in process heat gained by system is 350 j find the change in internal energy​

Answer 1

Answer:

A piston is compressed from a volume of 8.30 L to 2.80 L against a constant pressure of 1.90 atm. In the process, there is a heat gain by the system of 365 J.

work = PdV

work = (1.90 atm) (-5.5 litres)

work = - 10.45 litre.atm

Answer 2

Answer:

The answer is -750 J.

Explanation:

The given problem is based on First Law of Thermodynamics.

First, we need to calculate the pressure-volume work done on the system during compression.

W = -P.dV

Pressure = P = 2 bar = 200000 Pa

Volume change = dV = (2.8 - 8.3) L = (2.8 - 8.3) x 0.001 $m^3$

Hence,

W = -200000 x (2.8 - 8.3) x 0.001

W = 1100 J

Now, given

Heat gained by the System = Q = 350 J

Change in internal energy of the system is given by:

Change in internal energy = ΔU = Q - W

Hence,

Change in internal energy = ΔU = 350 - 1100 = -750 J

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