Question

to prepare 250 ml of m/20 oxalic acid solution​

Answer 1

Molecular formula of solid crystalline oxalic acid: H2C2O4, 2H2O. Its Molecular Wt. 126. Hence, to prepare 250 ml M/20 oxalic acid solution 126*250/(20*1000) = 1.575 gram of oxalic acid is to be dissolved in water in a 250 ml volumetric flask.

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Answer 2

Formula of oxalic acid  =H2C2O4, 2H2O

Molecular mass of oxalic acid =126gm

for preparing 1000 ml of oxalic acid :- weight of oxalic acid = 126 gm

∴ to prepare 250 ml of oxalic acid of m/20 solution

required quantity of  oxalic acid crystals will be :-

             =126/1000×250×0.2 gm

               = 3.150 ×0.2 gm

                =6.3 gm

Ans:- To prepare 250 ml of m/20 oxalic acid solution​ we need 6.3 gm of oxalic acid crystals.