Question

To prepare 250ml of m/20 oxalic acid solution with its help determine molarity and strength of kmno4 solution

Answer 1

option b) 294

hope you have got answer

Answer 2

Hello dear,

● Answer with Explaination-
Balanced molecular eqn is-
2KMnO4 + 2H2SO4 + 5(COOH)2 ---> K2SO4 + 2MnSO4 + 18H2O + 10CO2

Let, x = volume of KMnSO4 required for titration

(a) Molarity-
M(KMnSO4)×V(KMnSO4) / M(oxalic acid)×V(oxalic acid) = 2/5
M(KMnSO4) = 1/20 × 250 × 2/5 / x
M(KMnSO4) = 5/x M

(b) Strength -
Strength(KMnSO4) = M(KMnSO4) × molecular mass
Strength(KMnSO4) = 790/x g/l

Hope this is useful...