Question

Tom and Alice are the parents of four children. Tom has earlobes that are not attached to the side of his head, which is a dominant trait. Alice has earlobes that are attached, which is a recessive trait. Use the two Punnett squares ("E" represents the dominant earlobe gene, and "e" represents the recessive earlobe gene) to answer the following questions

Answer 1

Answer:

TOM                      Alice >>  Parents

E                               e  >>  Gametes

crossing

Ee * Ee

EE : homozygous dominant

Ee : heterozygous dominant

Ee :  heterozygous dominant

ee : homozygous recessive

Answer 2

the ratio will be

Genotype : 3:1 = Ear lobe free:attached ear lobe  

Phenotype: 1:2:1= EE:Ee:ee          

Explanation:

• The dominant character here is of tom which is attached ear lobe is denoted as -EE .

• The ressesive character are free ear lobe of alice represented as- ee.

• So when we cross EE × ee we get - Ee in F1 progeny and in F2 progeny we get : - ee--1

       - EE--1

       -Ee---2

• So we get genotype as 3:1 and phynotype as 1:2:1.