top of the tower and ends of a bucket in the form of a frustum of cone are 10 cm and 30 cm respectively if it's height 24 cm
Find the area of the metal sheet used to make a bucket
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Hii friend,
DIAMETER OF UPPER PART = 30 CM
RADIUS OF UPPER PART = D/2 = 30/2 = 15 CM
DIAMETER OF LOWER PART OF THE BUCKET = 10 CM
RADIUS OF LOWER PART (r) = D/2 = 10/2 = 5 CM
HEIGHT OF THE BUCKET = 24 CM
SLANT HEIGHT OF THE BUCKET = ✓(H)²+ ( R-r)² = ✓ (24)² + (15-5)² = ✓576 + 100 = ✓676 = 26 CM.
AREA OF METAL SHEET USED FOR MAKING THE BUCKET = CSA OF BUCKET+ AREA OF BOTTOM OF THE BUCKET...
= πL(R+r) + πr²
= 3.14 × 26 ( 15+5) + (3.14 × 5×5)
= 3.14 × 26 × 20 + 78.5
= 1632.8 + 78.5 = 1711.3 CM²
HENCE,
1711.4 CM² METALLIC SHEET IS USED FOR MAKING THE BUCKET......
DIAMETER OF UPPER PART = 30 CM
RADIUS OF UPPER PART = D/2 = 30/2 = 15 CM
DIAMETER OF LOWER PART OF THE BUCKET = 10 CM
RADIUS OF LOWER PART (r) = D/2 = 10/2 = 5 CM
HEIGHT OF THE BUCKET = 24 CM
SLANT HEIGHT OF THE BUCKET = ✓(H)²+ ( R-r)² = ✓ (24)² + (15-5)² = ✓576 + 100 = ✓676 = 26 CM.
AREA OF METAL SHEET USED FOR MAKING THE BUCKET = CSA OF BUCKET+ AREA OF BOTTOM OF THE BUCKET...
= πL(R+r) + πr²
= 3.14 × 26 ( 15+5) + (3.14 × 5×5)
= 3.14 × 26 × 20 + 78.5
= 1632.8 + 78.5 = 1711.3 CM²
HENCE,
1711.4 CM² METALLIC SHEET IS USED FOR MAKING THE BUCKET......
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