total mechanical energy of a freely feeling body
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State the law of conservation of energy. Show that the energy of a freely falling object is conserved.
Asked by Topperlearning User | 20th May, 2015, 11:49: AM
Expert Answer:
Law of conservation of energy - Energy can neither be created nor be destroyed; it can only be transformed from one form to another.
Consider a body of mass m placed at A.
h = AB is the height of the body above the ground
u = 0 is initial velocity at A
v1 = velocity of body at C
v = velocity of body at B, i.e., just above the ground
(i) At point A
PEA = mgh
KEA = 0
Total mechanical energy at A, EA = PEA + KEA = mgh + 0 = mgh
(ii) At point C
v12-0 = 2gs
v12 = 2gs
KEC =
PEC = mg(h-s)
Total mechanical energy at C, EC = PEC + KEC = mg(h-s) + mgs = mgh
(iii) At point B
v2-02 = 2gh
v2 = 2gh
KEB =
PEB = 0
Total mechanical energy at B, EB = PEB + KEB = 0 + mgh = mgh
The total mechanical energy of the body at A, B and C (also at any other point in the path AB) is the same. So, the total mechanical energy of the body throughout the free fall is conserved.