Question

Total no. of electrons in 4.4 gm of oxalate ion
1)0.05 NA
2)2.1 NA
3)2.2 NA
4)2.3 NA

Answer 1

Simply avagadro no of atom = atomic weight of oxylate ion
So 1g oxylate ion = avagadro no / atomic weight of oxylate ion so
4.4gm will have
4.4*avagadro no / atomic weight