total volume of 48g ozonide oxygen containing 16g o2 at ntp is
Answers
Answered by
0
As the volume occupied by 1mole of any gas under NTP is 22.4 L ... so 16g=0.5 mole hence 0.5mole of O2 will occupy 22.4/2 L of volume ... Explain with example.
Missing: t
Similar questions