Question

Tower stands vertically on the ground from a point which is 15 metre away from the foot of the tower the angle of elevation of the top of the tower is 45 degree what is the height of the tower ​

Answer 1

Let the height of tower be h m

so AB=hm

Distance of the point from

foot of tower = 30m

CB=30m

Angle of elevation =45

∘

∠ACB=45

∘

Since tower is vertical to ground

∠ABC=90

∘

Now tanC=

sideadjacenttoangleC

sideopptoangleC

tanC=

CB

AB

tan45=

CB

AB

1=

30

H

H=30

Hence height of tower = 30m

Answer = option C=30m