trajectory of kinetic energy of ball
Attachments:
Answers
Answered by
1
Kinetic Energy, K = ½mv2.
At the highest point, vertical component of velocity becomes zero and only the horizontal component is left that is given by
vx = v cosθ
θ = 45°, so cosθ = 1/√2
v x = v/√2
Kinetic energy K at the highest point = ½m(v/√2)2
= 1/2m * v^2 /2
= K/2
Hence K/2 is correct answer.
Similar questions