triangle abc ad is bisector of angle a show that triangle abd congruent cad
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in abd andcad
angle bad= angle cad[given]
ad =ad[common]
bd=dc[as median of adivides the side into two equal parts]
hence abd is congruent to triangle cad by sas criteria
angle bad= angle cad[given]
ad =ad[common]
bd=dc[as median of adivides the side into two equal parts]
hence abd is congruent to triangle cad by sas criteria
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Hola!
Given= triangle ABC and bisector (ad).
To prove = ABD congruent to CAD
Proof= In triangles ABD & CAD, we have
1. AD=AD (common)
2. angle BAD=CAD (Common angle)
3. BD=CD (AD bisects BC)
Therefore, triangle ABD=~ CAD
Hence proved!
Given= triangle ABC and bisector (ad).
To prove = ABD congruent to CAD
Proof= In triangles ABD & CAD, we have
1. AD=AD (common)
2. angle BAD=CAD (Common angle)
3. BD=CD (AD bisects BC)
Therefore, triangle ABD=~ CAD
Hence proved!
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