Question

triangle ABC is right angeled at C and AC= root 3 BC. prove that angle ABC = 600

Answer 1

ABC +45y - x+n=5x - x
$\sqrt{2 { {x \beta \pi}^{?} }^{2} }$
C-2=y+b=56 gh - 5x+h-y+x=0.x5
ABC =y+x