Triangle abc is right angle at b , ab= 6units aand angle c = 60° find ac , bc, angle a
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dharmendrasinghasr01
norinagrimchimarak79
6 days ago
Math
Secondary School
+5 pts
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Triangle abc is right angle at b , ab= 6units and angle c = 60° find ac , bc, and angle a
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arhankhan253588
Arhankhan253588Virtuoso
Answer:
Solution:
Given In ∆ABC, <ABC = 90°
AB = 6 units , BC = 8 units
By Phythogarian theorem:
i) AC² = AB²+BC²
= 6²+8²
= 36+64
= 100
=> AC = √100
=> AC = 10 units.
ii)sinA = BC/AC = 8/10
cosC = BC/AC = 8/10
cosA = AB/AC = 6/10
sinC = AB/AC = 6/10
Now ,
sinAcosC+cosAsinC
= \frac{8}{10}\times\frac{8}{10}+\frac{6}{10}\times\frac{6}{10}
= \frac{64}{100}+\frac{36}{100}
= \frac{64+36}{100}
= $\frac{100}{100}$
= $1$
Therefore,
sinAcosC+cosAsinC =1
Step-by-step explanation:
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