Triangle ABC is right angled at B and D is the midpoint of BC. prove that AC^2=4AD^2_3AB^2
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=AB^2 + BC^2/4
AD^2 - AB^2= BC ^2/4
4AD^2 - 4AB^2 = BC^2 - 1 EQUATION
AC^2 = AB^2+ BC ^2 (PYTH THEO) - 2 EQUATION
SUBSITUTUING THE VALUE OF 1 EQUATION IN 2 EQUATI
msrajput:
AC^2 = AB^2 + 4AD^2 - 4AB^2
AC^2=4AD^2-3AB^2
Sorry I was not able to complete the answer. But plz Mark it brainliast.
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