Question

triangle abc is such that <abc=35 . H lies on BC as such that the lenght of HC is twice that of BH . Find <ACB.

pls help . will mark brainliest ​

Answer 1

Answer:

there you are

Step-by-step explanation:

if 2 right angled triangles are formed, you can use tangent of the angles to solve it

tan (35) = AH/BH

tan(<ACH) = AH/HC = AH/2BH

this means

tan(35)* BH = tan(<ACH) * 2BH

if you solve it, <ACH will be 19.3 degrees

(note <ACH is the same as <ACB)