Question

triangle JKL has vertices J(2, 3), K(3, 3). A translation maps the point J to J' (4, 3). what are the coordinates of K'?

Answer 1

Answer:

(5, 3)

Step-by-step explanation:

J(2, 3) -----> J'(4, 3)

2 + $k_{x}$ = 4 ⇒ $k_{x}$ = 2

3  + $k_{y}$ = 3 ⇒ $k_{y}$ = 0

Thus, the translation rule is A(x, y) ----> A'(x + 2, y + 0)

K'(3 + 2, 3 + 0) = K'(5, 3)