triangle pqr right angled at p o p = 7 cm and O P O - B2 = 1 cm determine the values of sin and Cos q
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Answer:
Step-by-step explanation:
let
OQ= x cm then
PQ = 1+x
by Pythagoras theorem we get
down that pic is here on this place
on solving it we get value of x which is
x= 24
so PQ = 24
OQ = 25
as we know all 3 sides we can calculate sin Q and cos Q which are
sin Q = (7/25)
cos Q = (24/25)
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