Trignometry que no. 7 fast please
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= 1 + tan2 A / 1+ cot2A
= sec2A/cos2A
Change in form of sin and cos
= 1/cos2A / 1/sin2A.
= 1/cos2A * sin2A/ 1
= tan2 A
Bhai theeta nhi diya that isliye A le liye
= sec2A/cos2A
Change in form of sin and cos
= 1/cos2A / 1/sin2A.
= 1/cos2A * sin2A/ 1
= tan2 A
Bhai theeta nhi diya that isliye A le liye
Answered by
3
Hey mate,..
Here's your answer,..
your answer is in the above attachment,...
before u see,..
just recall the formula,
2sin(@)cos(@)=sin2(@)
and the trigonometric identities,..such as
tan^2(t) + 1 = sec^2(t)
1 + cot^2(t) = csc^2(t)
Hope it helped you
pls mark me as the brainliest,...
Here's your answer,..
your answer is in the above attachment,...
before u see,..
just recall the formula,
2sin(@)cos(@)=sin2(@)
and the trigonometric identities,..such as
tan^2(t) + 1 = sec^2(t)
1 + cot^2(t) = csc^2(t)
Hope it helped you
pls mark me as the brainliest,...
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vhpsharitha:
pls mark me as the brainliest
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