Question

trigonometric equations
plz solve

Answer 1

Hey dear ☺️

Here your answer

2sin²@ = 3cos@

2(1-cos²@) = 3cos@

2-2cos²@= 3cos@

2cos²@+3cos@-2=0

2cos²+4cos@-cos@-2=0

2cos@( cos@+ 2) - 1(cos@+2)=0

(2cos-1)(cos@+2)=0


2cos@-1=0 or cos@+2=0


Cos@= 1/2 or cos@= - 2


But cos@=-2 is not possible

& cos@= 1/2 is possible


Cos@= 1/2

@= cos¯1/2

@= π/3

Hope it helpful