Question

TU ?
ose
(9 - 11): Read the given information
and answer the following questions.
A test tube is in the form of a right
circular cylinder, surmounted by a
cone. The diameter of the cylinder is
24 m. The height of the cylindrical
portion is 11m, while the vertex of the
cone is 16 m above the ground.
9. Find the C.S.A of the cylindrical por-
tion.
la-
and slant height and area​

Answer 1

Answer:

hi

Step-by-step explanation:

1318.8 sq,m,

Step-by-step explanation:

We are given that A tent is in form of a right circular cylinder surmounted by a cone.

Diameter of cylinder = 24 m

Radius of cylinder = \frac{24}{2} = 12 m

2

24

=12m

Height of cylinder = 11 m

CSA of cylinder = 2 \pi r h2πrh

= 2 \times 3.14 \times 12 \times 112×3.14×12×11

= 828.96 m^2828.96m

2

Radius of cone = 12 m

The vertex of the cone is 16 m above the ground.

The height of cone =16- Height of cylinder = 16- 11 = 5 m

Curved surface area of cone = \pi r \sqrt{h^2+r^2}πr

h

2

+r

2

=

= 489.84 m^2489.84m

2

Total area of canvas required =

Hence the area of the canvas required for the tent is 1318.8 sq,m,