Question

TU U UUTUU US UM
. Five balls bearing numbers 1, 2, 3, 4, 5 are put in a jar.
(i) What is the probability of getting an even number when one ball is taken out?
(ii) Find the probability of getting an odd number when a ball is taken out.
(111) Is the sum of these two probabilities equal to 1?​

Answer 1

Answer:

sample space = 5

Let the event of getting an even no. be A

p( A) = NA/ NS

= 2/5

Let the event of getting an odd number be B

p(B)= NB/NS

= 3/5

Yes the sum of these possibilities is equal to 1

Answer 2

Given,

Total balls = 5

Numbers on balls = 1, 2, 3, 4, 5

To Find,

The probability of getting an even number when one ball is taken out=?

The probability of getting an odd number when a ball is taken out =?

Is the sum of these two probabilities equal to 1 =?

Solution,

Number of balls with an even number = 2 [2,4]

The probability of getting the ball with an even number = 2/5

Number of balls with an odd number = 3 [1,3,5]

The probability of getting an odd number when a ball is taken out = 3 / 5

Sum of both probability = 2 / 5 + 3/5

Sum of both probability =  (2 + 3) / 5

Sum of both probability = 5 / 5

Sum of both probability = 1

Hence, The probability of getting an even number or odd number when one ball is taken out is 2 / 5 and 3/5 respectively. The sum of these two possibilities is equal to 1.