Question

Two 6v 2 ohm batteries are connected in series aiding this combination can be replaced by a single equivalent current generator and a parallel resistance of

Answer 1

Answer:

5 mA

Explanation:

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Answer 2

The equivalent battery will be have voltage of 6 V and a parallel resistance of 1 Ω

The voltages of the two batteries are = 6 V

The internal resistance of the batteries are = 2 Ω

We know, if two cells having voltages E₁ and E₂ and internal resistances r₁ and r₂ are connected in series, then the equivalent voltage of the batteries will be,

E = $\frac{E_1r_1+E_2r_2}{r_1+r_2}$

According to this formula, the equivalent voltage of the given batteries will be,

E = $\frac{2*6+2*6}{2+2}$

⇒ E = 6 V

And the parallel resistance will be =2/2 Ω

                                                         = 1 Ω