Math, asked by hazmanam9031, 1 year ago

Two adjacent angels of a parallelogram are in the ratio 2:3. Find the measure of each of it's angles.

Answers

Answered by listedsangam2004
6
Let the ratio be x
now we have, 2x and 3x

In a parallelogram we know that opposite sides are parallel.

so now we have, 2x , 3x, 2x, 3x

now by using exterior angle property

2x+3x+2x+3x = 360
10x = 360
x = 360/10
x= 36

2x = 72
3x = 108

plz mark as brainlist..

malagupta: 2x+3x+2x+3x=10x kaise huva ye to
malagupta: 13x hona chahiye
malagupta: sorry by chance mistake ho gayi
Answered by Anonymous
0

let the 4 angles of the parallelogram be∠A=  2x and ∠B=3x

in a parallelogram, ∠A = ∠C and ∠B = ∠D

Therfore 4 angles of the parallelogram are 2x,3x,2x and 3x

sum of angles in a parallelogram = 360 deg

2x+2x+3x+3x = 360

10x = 360

x = 36 deg

the angles are 2(36deg), 3(36deg), 2(36deg) and 3(36deg)

72°,108°,72° and 108°



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