two alternative sides of a rectangle polygon , when produced to , meet 120°. find exterior angles and number of sides.
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In a regular polygon all the exterior angles have the same measure.
When two alternate sides of a polygon are extended a triangle.
If AB, BC and CD are the sides of a regular polygon and AB and CD when produced meet at P forming a right triangle.
Now, in △CPB,∠PCB=∠PBC=45o
Therefore, exterior angle of the polygon = 45o
Exterior angle of a regular polygon = n360o
=>45o=n360o
=>n=8
Number of sides of the polygon = 8
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