Two atoms in a molecule are bonded to
bonded to a third
atom as shown. Find the distance d between the
centres of the two otom to the nearest whole.
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Step-by-step explanation:
Given.
if two adjacent sides are equal that is 128 .
coordinates (X,Y) and coordinates (128,0). is at same distance to origin (0,0)
To find the distance "d":-
we first find the values of x and y
we know that: from origin the distance between co.(X,y) is 128.
that mean . √(x-0)²+(y-0)² =128 unit
so, √x²+y² = 128 unit
x²+y²=128²------------1st eq.
now , the distance d between co. (128,0) and co.(X,y) is....
√(x-128)²+(y-0)² = d
x²+128²-256x+ y² =d²--------2nd eq.
putting the value of first eq. in second eq.
128²+128²-256x =d²
256(64+64-x)=d²
√256(128-x)=d
16√128-xpm=d [Answer]
I have tried my best to solve it at my level of 10th ..
it may be use full for you..
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