Two balls of different masses are thrown vertically upward with same initial speed.
Which one will rise to a greater height? explain briefly
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heya friend!!☺☺
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here's your answer!!☺☺
Both rise to the same height, because the bigger mass need more energy to reach that same height, and you indeed gave more energy to it when you threw it with same velocity as the lighter weight.
E1=1/2m1u² ,E1=1/2m1u² & E2=1/2m2u²
Now since m2>m1m2>m1, we get E2>E1E2>E1. So the larger mass is given more energy to reach the same height, and it was harder for you throwing it upwards with same velocity v.
Now since the energy is conserved,
m1gh1= E1m1gh1= E1 and m2gh2= E2m2gh2= E2
m1gh1=1/2m1u²
m2gh2=1/2m2u²
gh1=u²/2. , & gh2=u²/2
Notice that mass is cancelled from both sides, so it has no say in the matter. Also since the RHS of two sides is same -
gh1=gh2
h1=h2
Thus the height achieved by both the masses is same.
This is also the reason why none of the kinematic equations have mass in it.
_______________________________
hope it helps you!!☺☺
_____________________________
_____________________________
here's your answer!!☺☺
Both rise to the same height, because the bigger mass need more energy to reach that same height, and you indeed gave more energy to it when you threw it with same velocity as the lighter weight.
E1=1/2m1u² ,E1=1/2m1u² & E2=1/2m2u²
Now since m2>m1m2>m1, we get E2>E1E2>E1. So the larger mass is given more energy to reach the same height, and it was harder for you throwing it upwards with same velocity v.
Now since the energy is conserved,
m1gh1= E1m1gh1= E1 and m2gh2= E2m2gh2= E2
m1gh1=1/2m1u²
m2gh2=1/2m2u²
gh1=u²/2. , & gh2=u²/2
Notice that mass is cancelled from both sides, so it has no say in the matter. Also since the RHS of two sides is same -
gh1=gh2
h1=h2
Thus the height achieved by both the masses is same.
This is also the reason why none of the kinematic equations have mass in it.
_______________________________
hope it helps you!!☺☺
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