Question

Two balls of equal mass of 4kg are moving with equal speed of 4m/s ea

Answer 1

Answer:

m

1

=m

2

=1.5 kg

u

1

=2.5 ms

−1

u

2

=2.5 ms

−1

Total mass of the combined system, M=m

1

+m

2

=2×1.5=3kg

Let the velocity of the combined system after the collision be v

Applying conservation of momentum before and after the collision :

m

1

u

1

−m

2

u

2

=Mv

1.5×2.5−1.5×2.5=3v

⟹v=0

Explanation:

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