English, asked by google1818, 1 year ago

Two blocks of masses m1 and m2 are connected to each other through a light spring .If we pushes mass m1 with force F and cause acceleration a1 in mass m1,what will be the magnitude of the acceleration in m2?

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Answered by shashankavsthi
52
hope this will help you...

further query ask in comment section
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google1818: Why in the second equation we have not taken F-T or T-F=m2a2?
shashankavsthi: because action and reaction force always acts on diffrent bodies
shashankavsthi: and force f is applied on mass m1 only.
google1818: thanks a lot.
shashankavsthi: you must have to thanks when someone help u....
google1818: i already did.
shashankavsthi: sorry haven't seen it..my mistake
Answered by phillipinestest
19

Answer: { a }_{ 2 }\quad =\quad \frac { F\quad -\quad { m }_{ 1 }{ a }_{ 1 } }{ { m }_{ 2 } }

The two blocks are { m }_{ 1 }\quad and\quad { m }_{ 1 }

The force F is acting on block { m }_{ 1 } with acceleration { a }_{ 1 }

Let us take the acceleration acting on mass { m }_{ 2 } as { a }_{ 2 }

F\quad -\quad T\quad =\quad { m }_{ 1 }{ a }_{ 1 }\quad \longrightarrow \quad \left( i \right)

On rearranging, we get

T\quad =\quad F\quad -\quad { m }_{ 1 }{ a }_{ 1 }

T\quad =\quad { m }_{ 2 }{ a }_{ 2 }\quad \longrightarrow \quad \left( ii \right)

On equating, we get

F\quad -\quad { m }_{ 1 }{ a }_{ 1 }\quad =\quad { m }_{ 2 }{ a }_{ 2 }

{ a }_{ 2 }\quad =\quad \frac { F\quad -\quad { m }_{ 1 }{ a }_{ 1 } }{ { m }_{ 2 } }

Thus, we found the magnitude of acceleration { a }_{ 2 }

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