Two bodies are in equilibrium when suspended in water from the arms of a balance. the mass of one body is 36 g and its density is 9 g/cc. if the mass of the other is 48 g, its dendity is
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Let the objects be x and y
Density of A=mass of A/volume of A
9g/cc=36g÷v
9v=36g
V=36÷9
V=4
We get the volume of water =4
Both r equilibrium in water so....
Density of B=mass of B ÷volume of B
=48g÷4
12gm/cm^3
Density of A=mass of A/volume of A
9g/cc=36g÷v
9v=36g
V=36÷9
V=4
We get the volume of water =4
Both r equilibrium in water so....
Density of B=mass of B ÷volume of B
=48g÷4
12gm/cm^3
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