Two bodies are in the ratio 3:4. When a force is applied on the first body, it moves with an acceleration of 6 ms². When the same force is applied on the second body, what acceleration would it produce?
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Let us name the 2 bodies as A and B
If the mass of A is 3m then the mass of B will be 4m as the ratio of their masses is 3:4
Let F be the force which is applied on A
Applying newton's 2nd law of motion on A ,we get :
F=3m×6
F=18m
Hence m=F/18
Now applying 2nd law on B, we get
F=4ma where a is the acceleration of B
Substituting the value of m as F/18, we have
F=4×F/18a
a=18/4=4.5metre per second square
Hope it helps you
Please mark my answer as brainliest
If the mass of A is 3m then the mass of B will be 4m as the ratio of their masses is 3:4
Let F be the force which is applied on A
Applying newton's 2nd law of motion on A ,we get :
F=3m×6
F=18m
Hence m=F/18
Now applying 2nd law on B, we get
F=4ma where a is the acceleration of B
Substituting the value of m as F/18, we have
F=4×F/18a
a=18/4=4.5metre per second square
Hope it helps you
Please mark my answer as brainliest
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