Two bodies are projected with the same
speed of 10 ms. If one to projected at an angle
45° and other is at 15°with the
horizontal, then the difference of their horizontal range
will be
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Answer:
As in the case of projectiles, we know that the formula for maximum height is:
h=(u^2)sin(2theta) / g , where theta is the angle with which the projectile was projected with the horizontal.
This formula states that the maximum height reached by the projectile is directly proportional to the sine of double angle.
So, the ratio will be sin(60)/sin(120)= 1
Also, as these angles are complementary, i.e. 60+30 = 90 degrees
The maximum height reached by these projectiles will be same.
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