Two bodies of different masses m (a) and m (b) are dropped from two different heights viz... A and B. The ratio of the times taken by the two to drop through these distances is?
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Height are A and B.
Both bodies get accelerated towards earth with acceleration equal to g.
Time of flight =✓(2h/g)
For Body A
T(a) =√(2A/g)
For Body B
T(b) =√(2B/g
T(a)/T(b) =
√(2A/g)/√(2B/g)
= √(A/B)
Both bodies get accelerated towards earth with acceleration equal to g.
Time of flight =✓(2h/g)
For Body A
T(a) =√(2A/g)
For Body B
T(b) =√(2B/g
T(a)/T(b) =
√(2A/g)/√(2B/g)
= √(A/B)
simrankaurgill:
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oh mistake
i haven't read full question
1) a:b 2) m(a)/m(b): b/a
3) Sq root of a: Sq root of b 4)a^2 :b^2
3) Sq root of a: Sq root of b 4)a^2 :b^2
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