Question

two bodies of different masses m1 and m2 are dropped from two different heights "a" and "b"

what is the ratio of time taken by the two bodies to drop through these distances

Answer 1

since it is free fall so there is no role of mass.
applying second equation of motion for both the masses

for m1 => a = (1/2)g(t1)^2 -----------1
for m2 => b = (1/2)g(t2)^2 -----------2
dividing both the equation t1/t2 = √(a/b)

Answer 2

Answer:

$\sqrt{a} : \sqrt{b}$

=> reffer to the images for explanation