two bodies of mass 1 kg and 2kg respectively are placed at a separation of 1 M find the acceleration of the body assuming only gravitational forces to act..
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Here is your answer
here,
M= 2kg , m= 1kg, d= 1meter
We know that,
F= GMm/d^2
ma=GMm/d^2
a= GM/d^2
= (6.67×10^-11 ×2/1^2)m/s^2
= 13.35× 10-11 m/s^2
=1.335×10^-10 m/s^2
hence, acceleration produced= 1.335×10^-10 m/s^2
here,
M= 2kg , m= 1kg, d= 1meter
We know that,
F= GMm/d^2
ma=GMm/d^2
a= GM/d^2
= (6.67×10^-11 ×2/1^2)m/s^2
= 13.35× 10-11 m/s^2
=1.335×10^-10 m/s^2
hence, acceleration produced= 1.335×10^-10 m/s^2
abhaygoel71:
welcome
hmm
it is correct na?
thanks for marking my answer as brainliest
u r welcome
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