Two bodies of masses 6kg and 4kg are connected to a string passing over a light frictionless pulley, then find acceleration and thrust on the pulley. ( g=10m/s^2)
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Since 6kg is heavier than 4 kg so it will accelerate down while 4 kg will accelerate up
So the equation of net force on 6kg is given as
6×10−T=6a
equation of net force on 4kg is given as
T−4×10=4a
now add the above two equations
6×10−(4×10)=(6+4)×a
60 - 40 = 10a
a = 2m/s
2
So 6 kg will accelerate downwards while 4 kg will accelerate upwards
with acceleration 2 m/s
2
now in order to find the tension force
T−4×10=4×2
T = 48N
So the tension in the string is 48 N
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