Two brass balls of masses 2kg and 0.5kg experience a force of attraction of 2N.When the distance between their centres is doubled.The force of attraction is
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force between the balls= 2N
g=GmM/r²
g'=GmM/(2r)²=GmM/4r²
by equating g and g'
GmM/r²=GmM/4r²
so g=g'/4 or 4g=g'
if u got confused then in the equation just cancel out GmM/r² and u get the ratio 1:1/4
as g' is the new value of g after doubling distances, so let's substitute 2N with g as it is its value if distance is not doubled.
so 2N=4g'
g'=1/2 N
hope this helped
mark as brainliest
g=GmM/r²
g'=GmM/(2r)²=GmM/4r²
by equating g and g'
GmM/r²=GmM/4r²
so g=g'/4 or 4g=g'
if u got confused then in the equation just cancel out GmM/r² and u get the ratio 1:1/4
as g' is the new value of g after doubling distances, so let's substitute 2N with g as it is its value if distance is not doubled.
so 2N=4g'
g'=1/2 N
hope this helped
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